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IBM Developing with IBM Enterprise PL/I Sample Questions:

1. In a multithreading environment, when can a deadlock occur between two threads, if at all?

A) It can neveroccur.
B) When they have both locked a resource that the other one requires
C) When they are operating synchronously
D) When both access the same memory area

2. What could be used when a structure is passed to a subroutine to verify that the area the structure
occupies in storage has not been overwritten?

A) Structure has eyecatchers at start and at end.
B) Structure is passed as an aggregate.
C) Structure has a length field at start.
D) Structure is passed as a pointer.

3. What is the output of the following program?
DCL A AREA(8000);
DCL 1 STR1 BASED(P),
2 STR1_LGTH BIN FIXED(31),
2 STR_CHAR CHAR(ALLOC_LGTH REFER(STR1_LGTH));
DCL ALLOC_LGTH BINFIXED(31);
DCL I FIXED BIN(31);
DCL P PTR;
ALLOC_LGTH = 100;
DO I = 1 TO 10;
ALLOC STR1 IN(A);
END;
PUT SKIP LIST(CSTG(A));

A) 1056
B) 1040
C) 8000
D) 1016

4. The following structure is used when writing a file on Intel architecture which is sent to the mainframe:
DCL 1 A,
2 B FIXED BIN(31),
2 C CHAR (100) VAR,
2 D FIXED BIN(31);
How must this structure be declared on the mainframe if the file is to be read correctly?

A) D CL 1 A,
2 B FIXED BIN(31) BIGENDIAN,
2 C CHAR (100) VAR,
2 D CHAR (10);
B) DCL1 A,
2 B FIXED BIN(31) LITTLEENDIAN,
2 C CHAR (100) VAR LITTLEENDIAN,
2 D CHAR (10);
C) DCL1 A,
2 B FIXED BIN(31) LITTLEENDIAN,
2 C CHAR (100) VAR,
2 D CHAR (10);
D) DCL1 A,
2 B FIXED BIN(31) BIGENDIAN, 2 C CHAR (100) VAR BIGENDIAN, 2 D CHAR (10);

5. Prerequisite:
A sorted input dataset with record length 100 contains at least one record for all the values '1', '2', '3' in
the first byte. The applied sort criteria is 1,100,ch,a.
Requirements:
1 .) All records with '1' in the first byte must be ignored.
2 .) All records with '2' in the first byte must be written to the output dataset.
3 .) If there is a '3' in the first byte, the program must not read more records.
4 .) The program must not abend or loop infinitely.
If the following code does not fulfill the requirements above, which would be the reason, if any?
DCL DDIN FILE RECORD INPUT;
DCL DDOUT FILE RECORD OUTPUT;
DCL 1 INSTRUC,
3 A CHAR(1),
3 * CHAR(99);
DCL EOF_IN BIT(1) INIT('0'B);
DCL (Z1,Z2,Z3,ZO) BIN FIXED(31) INIT(0);
ON ENDFILE(DDIN) EOF IN = '1'B;
READ FILE(DDIN) INTO (INSTRUC);
IF EOF_IN THEN LEAVE;
SELECT(INSTRUC .A);
WHEN('1') DO;
Z1 += Z1;
ITERATE LAB;
END;
WHEN('3') DO;
Z3 = Z3 + 1;
LEAVE;
END;
WHEN('2') DO;
Z2 = Z2 + 1;
WRITE FILE(DDOUT) FROM(INSTRUC);
END;
OTHER DO;
ZO = ZO + 1;
PUT SKIP LIST(INSTRUC.A);
END; END;/*SELECT*/
END;/*LOOP*/

A) The code fulfills the requirement.
B) The code does not fulfill the requirement, because the READ iteration will not be left when the first
record with '3' in the first byte appears.
C) The code does not fulfill the requirement, because the program will loop infinitely.
D) The code does not fulfill the requirement, because not all records with '2' in the first byte will be written
to the output dataset.

Solutions: